11x^2=x2+8x

Solution for 11x^2=x2+8x equation:

11x^2=x2+8x

We move all terms to the left:

11x^2-(x2+8x)=0

We add all the numbers together, and all the variables

11x^2-(+x^2+8x)=0

We get rid of parentheses

11x^2-x^2-8x=0

We add all the numbers together, and all the variables

10x^2-8x=0

a = 10; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·10·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*10}=\frac{16}{20}
=4/5
$